SOLUTION: 1. (x-3)squared=0.25 2. 9xsquared-25=0 3. 27-3x=2xsquared 4. write an algebraic equation for the given verbal expression: the perimeter of a rectangle whoes width is

Algebra ->  Equations -> SOLUTION: 1. (x-3)squared=0.25 2. 9xsquared-25=0 3. 27-3x=2xsquared 4. write an algebraic equation for the given verbal expression: the perimeter of a rectangle whoes width is       Log On


   

Question 145412: 1. (x-3)squared=0.25
2. 9xsquared-25=0
3. 27-3x=2xsquared
4. write an algebraic equation for the given verbal expression:
the perimeter of a rectangle whoes width is x and whose length is three times the width.
i need help with these algebra problems
can anyone show me how to do this and with anwser provided
thanks
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
(x-3)^2=.25
x-3=+-.5 sqrt of each side
x=3.5, x=2.5
.
9x^2-25=0
(3x+5)(3x-5)=0
3x=-5, 3x=5
x=-5/3, x=5/3
.
27-3x=2x^2
2x^2+3x-27=0
2*-27=-54 What two factors of -54 when added equal 3? +9 & -6
2x^2+9x-6x-27=0
x(2x+9)-3(2x+9)=0
(x-3)(2x+9)=0
x=3
2x=-9
x=-9/2
.
P=2L+2w
=6w+2w
=8w
.
Ed