SOLUTION: Allen bought 56 stamps at the post office in 37 cent and 20 cent denominations. If the total cost of the stamps was $18, how many of each denomination did Allen buy?
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: Allen bought 56 stamps at the post office in 37 cent and 20 cent denominations. If the total cost of the stamps was $18, how many of each denomination did Allen buy?
Log On
Question 145296: Allen bought 56 stamps at the post office in 37 cent and 20 cent denominations. If the total cost of the stamps was $18, how many of each denomination did Allen buy? Found 2 solutions by ankor@dixie-net.com, Alan3354:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Allen bought 56 stamps at the post office in 37 cent and 20 cent denominations. If the total cost of the stamps was $18, how many of each denomination did Allen buy?
:
Let x = no. of 37 cent stamps
Let y = no. of 20 cent stamps
:
Total no. of stamps given as 56, therefore:
x + y = 56
or
y = (56-x)
:
Total cost given as $18, therefore:
.37x+ 2.0y = 18
:
Substitute (56-x) for y and find x:
.37x + .20(56-x) = 18
:
.37x + 11.2 - .20x = 18
:
.37x - .20x = 18 - 11.2
:
.17x = 6.8
x =
x = 40 ea 37 cent stamps
and
56 - 40 = 16 ea 20 cent stamps
:
:
Check solution:
.37(40) + .20(16) = 18
You can put this solution on YOUR website! B=# of 37c stamps
L=# of 20c stamps
B+L = 56
37B+20L = 1800
------------
B=56-L
Substitute for B
37(56-L)+20L=1800
2072-37L+20L=1800
2072-17L=1800
-17L=-272
L=16
-----
B=56-L
B=40
