SOLUTION: Please help... I am totally lost! Evaluate each of the functions below at x = 1, 2, 4, 8, and 16. Plot the graph of each function. Classify each as linear, quadratic, polynomial

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Please help... I am totally lost! Evaluate each of the functions below at x = 1, 2, 4, 8, and 16. Plot the graph of each function. Classify each as linear, quadratic, polynomial      Log On


   



Question 145285: Please help... I am totally lost!
Evaluate each of the functions below at x = 1, 2, 4, 8, and 16. Plot the graph of each function. Classify each as linear, quadratic, polynomial, exponential, or logarithmic, and explain the reasons for your classifications. Compare how quickly each function increases, based on the evaluations and graphs, and rank the functions from fastest to slowest growing.
f(x) = x3 - 3x2 - 2x + 1
f(x) = ex
f(x) = 3x - 2
f(x) = log x
f(x) = x2 - 5x + 6
Thank you very much.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29+=+x%5E3+-+3x%5E2+-+2x+%2B+1

f(1)=-3, f(2)=-7, f(4)=9, f(8)=305, f(16)=3,297


Graph:
+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E3+-+3x%5E2+-+2x+%2B+1%29+

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f%28x%29=e%5Ex:


f(1)=2.71828, f(2)=7.38906, f(4)=54.59815, f(8)=2980.9579, f(16)=8886110.5205

Graph:

+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+exp%28x%29%29+

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f(x) = 3x - 2 :
f(1)=1, f(2)=4, f(4)=10, f(8)=22, f(16)=46


Graph:

+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+3x+-+2%29+
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f(x)=log(x):

f(1)=0, f(2)=0.30103, f(4)=0.60206, f(8)=0.90309, f(16)=1.20412


Graph:
+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+log%2810%2Cx%29%29+

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f(x) = x^2 - 5x + 6:
f(1)=2, f(2)=0, f(4)=2, f(8)=30, f(16)=182


Graph:

+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2+-+5x+%2B+6%29+
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Rank from fastest growing to slowest growing:

1) f%28x%29=e%5Ex
2) f%28x%29=x%5E3+-+3x%5E2+-+2x+%2B+1
3) f%28x%29=x%5E2+-+5x+%2B+6
4) f%28x%29=3x-2
5) f%28x%29=log%28%28x%29%29