Question 145244: Tutor can you help please?
Write an equation for the line that passes through (3, -2) and (7, 6)
Thank you Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Solve for the slope, m.
m = (y2-y1)/(x2-x1)
m = (6-(-2))/(7-3)
m = 8/4 = 2
Use either point.
y-y1 = m(x-x1)
y-6 = 2(x-7)
y-6 = 2x-14
2x-y = 8
