SOLUTION: What is the directrix of the parabola with the equation y+3= 1/10 (x+2)^2?

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Question 145226: What is the directrix of the parabola with the equation y+3= 1/10 (x+2)^2?
Answer by Edwin McCravy(20062) About Me  (Show Source):
You can put this solution on YOUR website!
What is the directrix of the parabola with the equation y+3= 1/10 (x+2)^2?

What you have to know about parabolas in standard form:

1: Parabolas whose equations are in the standard form

%28x-h%29%5E2+=+4p%28y-k%29

opens upward if p+%3E+0 and downward if p+%3C+0

They have vertex (h, k), focus (h, k+p), and
the directrix is the horizontal line whose equation
is y=k-p

2: Parabolas whose equations are in the standard form

%28y-k%29%5E2+=+4p%28x-h%29

opens rightward if p+%3E+0 and leftward if p+%3C+0

They have vertex (h, k), focus (h+p, k), and
the directrix is the vertical line whose equation
is x=h-p.


Your equation

y%2B3=+%281%2F10%29+%28x%2B2%29%5E2

can be placed in the standard form 1.

Multiply both sides by 10

10%28y%2B3%29=+10%2A%281%2F10%29%28x%2B2%29%5E2

10%28y%2B3%29=+cross%2810%29%2A%281%2Fcross%2810%29%29%28x%2B2%29%5E2

10%28y%2B3%29=+%28x%2B2%29%5E2

Swap sides:

%28x%2B2%29%5E2=10%28y%2B3%29

Compare to the standard equation in 1 above:

%28x-h%29%5E2+=+4p%28y-k%29

So -h=2 so h=-2,
4p=10 so p=10%2F4=5%2F2
-k=3 so k=-3
opens upward because p+=+5%2F2+%3E+0 

It has vertex (h, k) = (-2,-3)

It has focus (h, k+p) = (-2,-3+5%2F2) = (-2, -1%2F2)
the directrix is the horizontal line whose equation
is y=k-p or y+=+-3-%285%2F2%29 or y+=+-11%2F2

To draw the graph, plot the focus (-2, -1%2F2), the vertex(-2,-3) and
the directrix y=-11%2F2

 

Draw a line from the focus directly to the directrix. The
vertex should be the midpoint of this line.



Draw a square with that line being its left side:



Draw another square with that line being its right side:



Finally, draw the parabola through the vertex and the
upper corners of the two squares:



Edwin