SOLUTION: Find the eccentricity of the ellipse given by
{{{16x^2+25y^2=100}}}
I have tried:
{{{(16x^2)/100 + (25y^2)/100 = 1}}}
that reduces to:
{{{4x^2/25 + 1y^2/4 =1}}}
W
Algebra ->
Quadratic-relations-and-conic-sections
-> SOLUTION: Find the eccentricity of the ellipse given by
{{{16x^2+25y^2=100}}}
I have tried:
{{{(16x^2)/100 + (25y^2)/100 = 1}}}
that reduces to:
{{{4x^2/25 + 1y^2/4 =1}}}
W
Log On
that reduces to:
What do I do next? Please explain if you can! Thanks so very much!
Your error is in thinking that you are necessarily reducing the
fractions to lowest terms. Instead think of it as making the
numerators 1. Sometimes it amounts to reducing the fraction
but not always.
Do it this way instead. Go back to:
Get a coefficient where the is by
multiplying top and bottom of the first fraction by
, and get a coefficient where
the is on the second fraction by multiplying
top and bottom by , and we have this:
Now cancel and that leaves just 1 understood on top:
So we have
And we only need to reduce the fractions on the bottom
The larger denominator is , and since ,
we compare the above to:
So
Eccentricity of an ellipse = where
Eccentricity of this elipse =
Edwin