SOLUTION: Find the vertex and focus of the parabola given by
x^2 = -1/8y
This is what I tried:
4p = -1/8
then divide by 4 so
p = - 1/32
vertex = (0,0,)
focus = (0, -1/32)
Ple
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Quadratic-relations-and-conic-sections
-> SOLUTION: Find the vertex and focus of the parabola given by
x^2 = -1/8y
This is what I tried:
4p = -1/8
then divide by 4 so
p = - 1/32
vertex = (0,0,)
focus = (0, -1/32)
Ple
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Question 145167: Find the vertex and focus of the parabola given by
x^2 = -1/8y
This is what I tried:
4p = -1/8
then divide by 4 so
p = - 1/32
vertex = (0,0,)
focus = (0, -1/32)
Please let me know if I did this right, thanks! Answer by stanbon(75887) (Show Source):
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