SOLUTION: Can someone please help me with these math problems? i= imaginary
(2+3i) + (4-5i)
(4+3i)-((2+2i)
(4+3i)- (2-2i)
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-> SOLUTION: Can someone please help me with these math problems? i= imaginary
(2+3i) + (4-5i)
(4+3i)-((2+2i)
(4+3i)- (2-2i)
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Question 145125: Can someone please help me with these math problems? i= imaginary
(2+3i) + (4-5i)
(4+3i)-((2+2i)
(4+3i)- (2-2i) Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! Simply think of 'i' as a variable.
(2+3i) + (4-5i)
=2 + 3i + 4 - 5i
=6-2i (combine like-terms)
(4+3i)-((2+2i)
=4+3i-2-2i (distribute minus sign to terms inside parenthesis)
=2+i (combine like-terms)
(4+3i)- (2-2i)
= 4+3i-2+2i (distribute minus sign to terms inside parenthesis)
= 2+5i
