SOLUTION: 1. i am supposed to simplify this. 1/3 the square root of 24 minus 2 the square root of 2/3. i dont know what to do. 2. i am supposed to solve this. the lenth of a

Algebra ->  Radicals -> SOLUTION: 1. i am supposed to simplify this. 1/3 the square root of 24 minus 2 the square root of 2/3. i dont know what to do. 2. i am supposed to solve this. the lenth of a       Log On


   

Question 145116: 1.
i am supposed to simplify this.
1/3 the square root of 24 minus 2 the square root of 2/3.
i dont know what to do.
2.
i am supposed to solve this.
the lenth of a rectangle is 2x width. the area is 64 cm squared. i need to find the dimensions and round to the nearest hundredth. I dont know what to do .
Please help


Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
%281%2F3%29sqrt%2824%29-2sqrt%282%2F3%29

%281%2F3%29%5E2=1%2F9, so %281%2F3%29sqrt%2824%29=sqrt%2824%2F9%29=sqrt%28%288%2A3%29%2F%283%2A3%29%29=sqrt%288%2F3%29, so:




2. Area of a rectangle: A=LW. If length is twice the width and the area is 64, then L=2W and the area is A=%282W%29W=2W%5E2=64

Check your work by multiplying the value you determined for W by the value you determined for L. You have solved the problem correctly if your result is 64 and L is twice the value of W.

Divide both sides by 2 and take the square root of both sides giving you the value of W. Multiply that by 2 to get L.