Question 145109:  A personn invested 10,000.  The greater part is invested at 6% and the remainder at 5%.  The annual income from the greater part is $160 more than the annual income form the smaller part.  what is the smaller part of the the investment? 
 Answer by checkley77(12844)      (Show Source): 
You can  put this solution on YOUR website! .06X=.05(10,000-X)+160 
.06X=500-.05X+160 
.06X+.05X=660 
.11X=660 
X=660/.11 
X=$6,000 INVESTED @ 6%. 
10,000-6,000=4,000 INVESTED @ 5%. 
PROOF 
.06*6,000=.05*4,000+160 
360=200+160 
360=360 
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