SOLUTION: The owner of cool beans coffee shop mixes french roast coffee worth $9.00 per with Kenyan coffee worth $7.50 per pound in order to get 10 pounds of a mixture worth $8.40 per pound.

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Question 145097: The owner of cool beans coffee shop mixes french roast coffee worth $9.00 per with Kenyan coffee worth $7.50 per pound in order to get 10 pounds of a mixture worth $8.40 per pound. How much of each type of coffee was used?
number of pounds of french roast coffee_______
number of poundsof Kenyan coffee_____
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let f= pounds of french roast used
Let k= pounds of Kenyan used
%289f+%2B+7.5k%29%2F10+=+8.40
f+%2B+k+=+10
k+=+10+-+f
Substitute this value of k into the other equation
9f+%2B+7.5%2810+-+f%29%29%2F10+=+8.4
%289f+%2B+75+-+7.5f%29%2F10+=+8.4
1.5f+%2B+75+=+84
1.5f+=+9
f+=+6
k+=+10+-+f
k+=+10+-+6
k+=+4
The owner used 6 pounds of French roast and
4 pounds of Kenyan coffee