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| Question 145091:  On an 18-hole golf course, there are par-3 holes, par-4 holes, and par-5 holes. A golfer who shoots par on every hole has a score of 72. the sum of the number of par-3 holes and the number of par -5 holes is 8. How many of each type of hole are there on the golf course?
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! On an 18-hole golf course, there are par-3 holes, par-4 holes, and par-5 holes. # of holes equation: t + f + v = 18
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 A golfer who shoots par on every hole has a score of 72.
 par equation: 3t + 4f + 5v = 72
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 The sum of the number of par-3 holes and the number of par -5 holes is 8.
 Added info equation: t + v = 8
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 How many of each type of hole are there on the golf course?
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 You have three equations with three variables:
 t + f + v = 18
 t + 0 + v = 8
 3t+4f +5v = 72
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 Subtract 2nd equation from 1st to get:
 0 + f + 0 = 10 (so # of par 4 holes is 10)
 t + 0 + v = 8
 3t+4f +5v = 72
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 Subtract 3 times the 2nd from the 3rd to get:
 0 + f + 0 = 10
 t + 0 + v = 8
 0+ 4f +2v = 48
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 Since f = 10, substitute into the 3rd equation and solve for v:
 4*10 + 2v = 48
 2v = 8
 v = 4 (so # of par five holes is 4)
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 Since t + f + v = 18
 t + 10 + 4 = 18
 t = 4
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 t = 4
 f = 10
 v = 4
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 Cheers,
 Stan H.
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