SOLUTION: If the equation of a parabola is y = 8(x - 3)^2 + h, and its vertex is (3, -3), what is the value of h in the equation?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: If the equation of a parabola is y = 8(x - 3)^2 + h, and its vertex is (3, -3), what is the value of h in the equation?      Log On


   

Question 145007: If the equation of a parabola is y = 8(x - 3)^2 + h, and its vertex is (3, -3), what is the value of h in the equation?
Answer by shahid(44) About Me  (Show Source):
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if we look at its general formula y=a(x-m)^2+k which gives vertex (m,k)comparing this with given curve y=8(x-3)^2+h we get m=3 and k=h since vertex is (3,-3) gives k=-3 so h=-3 as h=k