SOLUTION: What is the y-coordinate of the vertex of a parabola with the following equation? y = x^2 - 6x + 14

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What is the y-coordinate of the vertex of a parabola with the following equation? y = x^2 - 6x + 14      Log On


   

Question 144998: What is the y-coordinate of the vertex of a parabola with the following equation?
y = x^2 - 6x + 14
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
See http://en.wikipedia.org/wiki/Parabola#Equations

k+=+%284ac-b%5E2%29%2F4a a = 1, b=-6 c =14
k+=+%2856-36%29%2F4
k++=+5