SOLUTION: How do I solve using the square root and radical sign? n^2-4n-4=0

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Question 144930This question is from textbook prentice hall algebra 1
: How do I solve using the square root and radical sign?
n^2-4n-4=0 This question is from textbook prentice hall algebra 1

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve using the square root and radical sign?
n^2-4n-4=0
n = [4 +- sqrt(16-4*1*-4)]/2
n = [4 +- 4sqrt(2)]/2
n = [2 +- 2sqrt(2)]
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Cheers,
Stan H.