SOLUTION: Find the domain of the function.
p(x)=x^3-x^2+x-9
What is the function of p?
a. {x x is a real number}
b. {x x is not equal to 0}
c. {x x is not equal to 9}
d. {x x>0}
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-> SOLUTION: Find the domain of the function.
p(x)=x^3-x^2+x-9
What is the function of p?
a. {x x is a real number}
b. {x x is not equal to 0}
c. {x x is not equal to 9}
d. {x x>0}
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Question 144839: Find the domain of the function.
p(x)=x^3-x^2+x-9
What is the function of p?
a. {x x is a real number}
b. {x x is not equal to 0}
c. {x x is not equal to 9}
d. {x x>0} Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
Looking at , we can see that there are no square roots, logs, and other functions where there are restrictions on the domain.
Also, we can see that the function does not have a division by x (or any combination of variables and constants).
So we don't have to worry about division by zero.
Since we don't have any restrictions on the domain, this shows us that the domain is all real numbers. In other words, we can plug in any number in for x
So the domain of the function in set-builder notation is:
In plain English, this reads: x is the set of all real numbers (In other words, x can be any number)
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