SOLUTION: In this question I need to use the “discriminant” to determine the number of solutions of the quadratic equation, and whether the solutions are real or complex. I need help please!

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: In this question I need to use the “discriminant” to determine the number of solutions of the quadratic equation, and whether the solutions are real or complex. I need help please!      Log On


   

Question 144829: In this question I need to use the “discriminant” to determine the number of solutions of the quadratic equation, and whether the solutions are real or complex. I need help please!!
4. m2 + m + 1 = 0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

D=b%5E2-4ac Start with the discriminant formula


From m%5E2%2Bm%2B1 we can see that a=1, b=1, and c=1


D=%281%29%5E2-4%281%29%281%29 Plug in a=1, b=1, and c=1


D=1-4%281%29%281%29 Square 1 to get 1


D=1-4 Multiply 4%281%29%281%29 to get %284%29%281%29=4


D=-3 Subtract 4 from 1 to get -3


Since the discriminant is less than zero, this means that there are two complex solutions