Question 144667This question is from textbook Prealgebra & Introductory Algebra
: The sum of the legs of a right triangle is 17 in. The longer leg is 2 more than twice the shorter. Th hypotenuse is 13 in. Find the length of each leg. Isn't the formula for a right triangle a^2 +b^2=c^2? From what I understand this is the way I would write to solve, but it doesn't make sense to me.
17=a^2+b^2+2
a^2+b^2= 13^2
Thanks for your help.
This question is from textbook Prealgebra & Introductory Algebra
Found 3 solutions by solver91311, scott8148, ankor@dixie-net.com: Answer by solver91311(24713) (Show Source): Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website! let x="shorter leg"
"The longer leg is 2 more than twice the shorter" __ 2x+2
"The sum of the legs of a right triangle is 17 in." __ x+2x+2=17
3x+2=17 __ 3x=15 __ x=5
substituting __ 2(5)+2=12
5,12,13 is a Pythagorean triple (like 3,4,5) __ 5^2+12^2=13^2 __ 25+144=169
Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The sum of the legs of a right triangle is 17 in. The longer leg is 2 more than twice the shorter. The hypotenuse is 13 in. Find the length of each leg.
:
Isn't the formula for a right triangle a^2 +b^2 = c^2? Yes it is, but we don't need it here.
:
It says,"The hypotenuse is 13 in." therefore
c = 13
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Let a = shorter leg
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then it says,"The longer leg is 2 more than twice the shorter."therefore
b = 2a+2
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"the sum of the legs of a right triangle is 17":
a + b = 17
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Substitute (2a+2) for b and 13 for c, find a:
a + (2a+2) = 17
:
3a + 2 = 17
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3a = 17 - 2
:
3a = 15
a = 
a = 5
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Find the longer leg (b):
b = 2(5) + 2
b = 12
:
We can confirm our solution using the pythag
Does 5^2 + 12^2 = 13^2?
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