SOLUTION: A developer purchased 70 acres of land for $900,000. If part cost $20,000 per acre and the remainder cost $10,000 per acre, how many acres did the developer buy at each price?

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Question 144633This question is from textbook Basic Technical Mathematics with Calculus
: A developer purchased 70 acres of land for $900,000. If part cost $20,000 per acre and the remainder cost $10,000 per acre, how many acres did the developer buy at each price? This question is from textbook Basic Technical Mathematics with Calculus

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
20,000x+10,000(70-x)=900,000
20,000x+700,000-10,000x=900,000
10,000x=900,000-700,000
10,000x=200,000
x=200,000/10,000
x=20 acres were bought for $20,000 per acre.
70-20=50 acres were bought for $10,000 per acre.
proof:
20,000*20+10,000*50=900,000
400,000+500,000=900,000
900,000=900,000