SOLUTION: four cards are randomly selected from a standard 52 car deck, what is the probability of getting 4 hearts or 4 cards lower than a 9, counting aces as 1?

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Question 144481: four cards are randomly selected from a standard 52 car deck, what is the probability of getting 4 hearts or 4 cards lower than a 9, counting aces as 1?

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
four cards are randomly selected from a standard 52 car deck, what is the probability of getting 4 hearts or 4 cards lower than a 9, counting aces as 1?

Let A be the event "to select 4 hearts"
Let B be the event "to select 4 cards lower than 9"

Then we use the formula

P%28A+or+B%29+=+P%28A%29+%2B+P%28B%29+-+P%28A+and+B%29

First we calculate P%28A%29

There are C%2852%2C4%29 ways to select 4 cards from a standard deck of 52. 

So C%2852%2C4%29 is the denominator of P%28A%29.

Now we need to find the numerator of P%28A%29.

There are C%2813%2C4%29 ways to select 4 hearts from 13 without regard to order.

So P%28A%29+=+%28C%2813%2C4%29%29%2FC%2852%2C4%29

Next we find P%28B%29, of getting 4 cards lower than a 9, counting aces as 1.

There are 8 card ranks lower than 9, and there are 4 suits, so that makes
32 cards which are lower than 9.  

There are therefore C%2832%2C4%29 ways to select 4 cards lower than 9 from the 32.

So P%28B%29+=+C%2832%2C4%29%2FC%2852%2C4%29

Next we find P%28AandB%29.

This is when all 4 cards selected are both lower than 9 and are also hearts.

There are C%288%2C4%29 ways to select 4 hearts from the 8 hearts lower than 9.

So P%28AandB%29+=+C%288%2C4%29%2FC%2852%2C4%29 

So now we can plug in the formula:

P%28A+or+B%29+=+P%28A%29+%2B+P%28B%29+-+P%28A+and+B%29

  
 
P%28A+or+B%29+=+715%2F270725+%2B+35960%2F270725+-+70%2F270725

P%28A+or+B%29+=+%28715%2B35960-70%29%2F270725

P%28A+or+B%29+=+36605%2F270725

which reduces to

P%28A+or+B%29+=+7321%2F54145+=+0.1352110075

Edwin