SOLUTION: I apologize - I didn't input these in correctly. Find the root 5vz^20. Possible answers are z, z^15, z^5 and z^4 Solve 3vz-2+4. Possible answers are {34/9}, {31/9}, {34/3} or

Algebra ->  Square-cubic-other-roots -> SOLUTION: I apologize - I didn't input these in correctly. Find the root 5vz^20. Possible answers are z, z^15, z^5 and z^4 Solve 3vz-2+4. Possible answers are {34/9}, {31/9}, {34/3} or      Log On


   

Question 144389: I apologize - I didn't input these in correctly.
Find the root 5vz^20. Possible answers are z, z^15, z^5 and z^4
Solve 3vz-2+4. Possible answers are {34/9}, {31/9}, {34/3} or zero
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

sqrt%285vz%5E20%29 Start with the given expression


sqrt%285%29sqrt%28v%29sqrt%28z%5E20%29 Break up the root


sqrt%285%29%2Asqrt%28v%29%2Az%5E10 Simplify sqrt%28z%5E20%29 to get z%5E10


z%5E10%2Asqrt%285%29%2Asqrt%28v%29 Rearrange the terms


z%5E10%2Asqrt%285%2Av%29 Combine the roots



So sqrt%285vz%5E20%29 simplifies to z%5E10%2Asqrt%285%2Av%29. In other words, sqrt%285vz%5E20%29=z%5E10%2Asqrt%285%2Av%29 as long as "v" and "z" are positive.



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You can't solve 3vz-2+4 since it is NOT an equation (it needs an equals sign). Also, if there was an equals sign, what variable are you solving for?