SOLUTION: hello i have a question on the equation of an Ellipse i have the equation of x^2-6x+y^2-12y+41=0 and i found out that the standard form was [(x-3)^2]/4+[(y-6)^2]/4 = 1 and i c

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: hello i have a question on the equation of an Ellipse i have the equation of x^2-6x+y^2-12y+41=0 and i found out that the standard form was [(x-3)^2]/4+[(y-6)^2]/4 = 1 and i c      Log On


   



Question 144338: hello
i have a question on the equation of an Ellipse
i have the equation of x^2-6x+y^2-12y+41=0
and i found out that the standard form was [(x-3)^2]/4+[(y-6)^2]/4 = 1
and i can't figure out if its horizontal or vertical
because the denominators are the same
is this an ellipse??
thank you for your help
i really appreciate it
i have a test
so please help me!

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
this is a special case of an ellipse __ it is a circle

circles are ellipses with zero eccentricity