Question 144318: solve the solution
y=3^(2x+1)
y=9^(4-2x)
do you make the powers = one another for 2x+1=4-2x Found 2 solutions by vleith, stanbon:Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website! Almost. just remember that 9 = 3^2
y=9^(4-2x)
y =(3^2)^(4-2x)
y = 3^(8-4x)
now set them equal and solve
You can put this solution on YOUR website! To equate the powers you have to have equal bases:
y=3^(2x+1)
y=9^(4-2x)
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y = 3^(2x+1)
y = 3^[2(4-2x)]
-----------------
2x+1 = 2(4-2x)
2x+1 = 8-4x
6x = 7
x = 7/6
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Cheers,
Stan H.