| 
 
 
| Question 144278:  Please help me solve: There are 50 dimes in a roll of dimes, 40 nickles in a rold of nickels, and 40 quarters in a roll of quarters.  Robert has a total of 12 rolls of coins wiht the total value of $70.  If he has 3 more rolls of nickles than dimes, how many of each roll of coins does he have?
 Found 2 solutions by  Alan3354, ankor@dixie-net.com:
 Answer by Alan3354(69443)
      (Show Source): Answer by ankor@dixie-net.com(22740)
      (Show Source): 
You can put this solution on YOUR website! There are 50 dimes in a roll of dimes, 40 nickels in a roll of nickels, and 40 quarters in a roll of quarters. Robert has a total of 12 rolls of coins with the total value of $70. If he has 3 more rolls of nickels than dimes, how many of each roll of coins does he have?: :
 total no. of rolls equation
 n + d + q = 12
 ;
 $Value equation:
 .05(40n) + .10(50d) + .25(40q) = 70
 :
 2n + 5d + 10q = 70
 :
 "he has 3 more rolls of nickels than dimes,"
 n = (d+3)
 :
 Replace n with (d+3) in both equations:
 (d+3) = d + q = 12
 2d + q = 12 - 3
 2d + q = 9
 and
 2(d+3) + 5d + 10q = 70
 2d + 6 + 5d + 10q = 70
 7d + 10q = 70 - 6
 7d + 10q = 64
 :
 Two equations, two unknowns, we can handle that, can't we.
 Multiply the 1st two unknown eq by 10, subtract the 2nd one
 20d + 10q = 90
 7d +  10q = 64
 -----------------subtracting eliminates q, find d
 13d + 0q = 26
 d =
  d = 2 rolls of dimes
 :
 See if you can find the no. of rolls of nickels and quarters now.
 Check your solutions in the $value equation.
 If you have difficulty, email me: ankor@dixie-net.com
 | 
  
 | 
 |