SOLUTION: i dont know how to start this problem. it tells me to graph the conic section. i know how to graph but i dont know how to format the equation. the equation is (y+4)^2 = x-1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: i dont know how to start this problem. it tells me to graph the conic section. i know how to graph but i dont know how to format the equation. the equation is (y+4)^2 = x-1      Log On


   

Question 144015This question is from textbook Mcdougal littell algebra 2
: i dont know how to start this problem. it tells me to graph the conic section. i know how to graph but i dont know how to format the equation. the equation is (y+4)^2 = x-1 This question is from textbook Mcdougal littell algebra 2

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
(y+4)^2 = x-1
:
Find the square root of both sides
y + 4 = sqrt%28x-1%29
:
y = +sqrt%28x-1%29 - 4
and
y = -sqrt%28x-1%29 - 4
:
+graph%28+300%2C+200%2C+-6%2C+10%2C+-10%2C+6%2C+-sqrt%28x-1%29-4%2C+sqrt%28x-1%29-4%29+