SOLUTION: Tutors please help me: THANK YOU solve the exponential equation 3^x2+^4x=1/27 and 28^x=10^-3x

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Tutors please help me: THANK YOU solve the exponential equation 3^x2+^4x=1/27 and 28^x=10^-3x      Log On


   

Question 143910: Tutors please help me: THANK YOU
solve the exponential equation 3^x2+^4x=1/27
and

28^x=10^-3x
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve the exponential equation 3^(x^2+4x) = 1/27
3^(x^2+4x) = 3^-3
x^2+4x=-3
x^2+4x+3=0
(x+3)(x+1) = 0
x = -3 or x=-1
Checking those possible answers:
x= -3 check out
x= -1 does not
------------------------
28^x=10^-3x
xlog28 = -3x
3x+xlog28 = 0
x(3+log28) = 0
x = 0
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Cheers,
Stan H.