SOLUTION: Hi hows everyone today! I need your help please.... Find the slope of any line perpendicular to the line through points (0, 4) and (-3, -6). Thanks a million!

Algebra ->  Graphs -> SOLUTION: Hi hows everyone today! I need your help please.... Find the slope of any line perpendicular to the line through points (0, 4) and (-3, -6). Thanks a million!      Log On


   

Question 143799: Hi hows everyone today! I need your help please....
Find the slope of any line perpendicular to the line through points (0, 4) and
(-3, -6).
Thanks a million!
Answer by nabla(475) About Me  (Show Source):
You can put this solution on YOUR website!
Find the slope of the line through the points first:
m=%28y2-y1%29%2F%28x2-x1%29=%28-6-4%29%2F%28-3-0%29=-10%2F-3=10%2F3
Now, orthogonality for lines is made by simply taking the negative reciprocal. That is, -3/10 will be the slope of any line perpendicular to the line through the points you supplied.
Just for fun let's write the equation for such lines as well and graph it.
original line: y=(10/3)x+4
And a perpendicular line would simply be y=(-3/10)x
graph%28+300%2C+200%2C+-5%2C+5%2C+-5%2C+5%2C+%2810%2F3%29x%2B4%2C+%28-3%2F10%29x%29