SOLUTION: How do I solve? Find the value of the discriminant to determine the number of real-number solutions for thi quadratic equation:
x^2-8x+3=0
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-> SOLUTION: How do I solve? Find the value of the discriminant to determine the number of real-number solutions for thi quadratic equation:
x^2-8x+3=0
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Question 143568This question is from textbook Prentice hall Algebra 1
: How do I solve? Find the value of the discriminant to determine the number of real-number solutions for thi quadratic equation:
x^2-8x+3=0 This question is from textbook Prentice hall Algebra 1
You can put this solution on YOUR website! How do I solve? Find the value of the discriminant to determine the number of real-number solutions for this quadratic equation:
x^2-8x+3=0
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a= 1 ; b = -8 ; c = 3
b^2-4ac = 64 - 4*1*3 = 52
Since the discriminant is positive the quadratic as two unequal Real Number
solutions.
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Cheers,
Stan H.
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