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Question 143555: find domain and range
f(x)=2-square root xsquared+3x+2divided by x squared+5x+4
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find domain and range
f(x)=2-square root xsquared+3x+2divided by x squared+5x+4
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y = [2*sqrt(x^2+3x+2)] / [x^2+5x+4]
y = [2*sqrt[(x+1)(x+2)] / [(x+4)(x+1)]
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Domain: x cannot be -1 or -4
x^2+3x+2 must not be negative; but it never is.
So, domain is "all Real Numbers except x=-1 and x=-4".
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Range: With those asymptotes all y values are possible
So, range is "all Real Numbers".
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Cheers,
Stan H.
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