SOLUTION: Carla can ride her bike 2 mph faster than Karen. It takes Carla 48 minutes less to travel 50 miles than it does Karen. What is Carla's rate (mph)? HELP MUCH APPRECIATED!!!!

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Carla can ride her bike 2 mph faster than Karen. It takes Carla 48 minutes less to travel 50 miles than it does Karen. What is Carla's rate (mph)? HELP MUCH APPRECIATED!!!!      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 143383This question is from textbook algebra: structure and method: book1
: Carla can ride her bike 2 mph faster than Karen. It takes Carla 48 minutes less to travel 50 miles than it does Karen. What is Carla's rate (mph)? HELP MUCH APPRECIATED!!!! This question is from textbook algebra: structure and method: book1

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
let x=Carla, so x-2=Karen

d=rt __ t=d/r

48 min is 48/60 or 4/5 hr

"It takes Carla 48 minutes less to travel 50 miles than it does Karen"
__ (50/x)+(4/5)=50/(x-2)

multiplying by 5x(x-2) __ 250x-500+4x^2-8x=250x __ subtracting 250x __ 4x^2-8x-500=0

dividing by 4 __ x^2-2x-125=0

use quadratic formula to find x