SOLUTION: An astronaut on the moon tosses a ball upwards; by how much will the height of the ball exceed 100 feet if the ball's heights follows:
h(t) = -2.6t^2 + 32.lt + 5.5
a. 0.1 fe
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h(t) = -2.6t^2 + 32.lt + 5.5
a. 0.1 fe
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Question 143329: An astronaut on the moon tosses a ball upwards; by how much will the height of the ball exceed 100 feet if the ball's heights follows:
h(t) = -2.6t^2 + 32.lt + 5.5
a. 0.1 feet
b. 5.6 feet
c. 105.6 feet
d. The ball never exceeds the 100-foot mark Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! An astronaut on the moon tosses a ball upwards; by how much will the height of the ball exceed 100 feet if the ball's heights follows:
h(t) = -2.6t^2 + 32.lt + 5.5
a. 0.1 feet
b. 5.6 feet
c. 105.6 feet
d. The ball never exceeds the 100-foot mark
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maximum height occurs when t = -b/2a = -32.1/(2*-2.6) = 6.173077 seconds
The height at that time is h(6.173077) = 104.58 ft
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The correct answer is 4.58 ft
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Cheers,
Stan H.
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