Question 143327: Part 2) Exercise #2 The null and alternate hypotheses are:
H(0): m(1) = m(2)
H(1): m(1) is not equal to m(2)
A random sample of 10 observations from one sample revealed a sample mean of 23 and a sample STDEV of 4. A random sample of 8 observations from another population revealed a sample mean of 26 and a sample STDEV of 5. At the 0.05 significance level, is there a difference between the population means? Also, (a) state the decision rule, (b) compute the pooled estimate of the population variance,(c) compute the t-test statistic, (d) state your decision about the null hypothesis, and (e) estimate the p-value.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Part 2) Exercise #2 The null and alternate hypotheses are:
H(0): m(1) = m(2)
H(1): m(1) is not equal to m(2)
A random sample of 10 observations from one sample revealed a sample mean of 23 and a sample STDEV of 4. A random sample of 8 observations from another population revealed a sample mean of 26 and a sample STDEV of 5.
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At the 0.05 significance level, is there a difference between the population means?
Since the p-value is greater than 5%, fail to reject Ho
The means are equal.
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(a) state the decision rule,
Critical values for 2-tail test with alpha=5% and df = 10+8-2=16: t = +/-2.120
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(b) compute the pooled estimate of the population variance,
The formula is on p 406 of your text.
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(c) compute the t-test statistic,
test stat: t = -1.4164...
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(d) state your decision about the null hypothesis,
Fail to reject Ho.
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(e) estimate the p-value.
p-value = 2P(-10 < t < -1.4164 with df= 16) = 0.17582...
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Cheers,
Stan H.
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