SOLUTION: Find all values of x in the interval 0 degrees is less than or equal to x which is less than 360 degrees that satisfy the equation 3cosx+sin2x=0.
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Question 143029: Find all values of x in the interval 0 degrees is less than or equal to x which is less than 360 degrees that satisfy the equation 3cosx+sin2x=0. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find all values of x in the interval 0 degrees is less than or equal to x which is less than 360 degrees that satisfy the equation 3cosx+sin2x=0.
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3cosx + sin2x = 0
3cosx + 2sinxcosx = 0
Factor:
cosx[3 + 2sinx] = 0
cosx = 0 or sinx = -3/2
Solutions in 0 <= x <= 360
If cos=0, x = 0 or 270
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sinx cannot equal -3/2
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Cheers,
Stan H.
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