SOLUTION: I do not understand polynomial notation. I somehow managed to get one of the questions right however I can't figure out the next one. Here is the question: Q(x)=x to the 2nd po

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I do not understand polynomial notation. I somehow managed to get one of the questions right however I can't figure out the next one. Here is the question: Q(x)=x to the 2nd po      Log On


   

Question 142905: I do not understand polynomial notation. I somehow managed to get one of the questions right however I can't figure out the next one.
Here is the question: Q(x)=x to the 2nd power - 3x + 4, Q(2), A(-3), Q(0)
If anyone can explain and help me I would be ever so grateful.
Found 2 solutions by vleith, cooper81:
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
I assume you meant Q(-3) not A(-3).
Given the expression Q%28x%29+=+x%5E2+-3x+%2B4
You are then asked to find the value of Q at 3 different values of x.
In each case, you substitute the given value of x into the expression.
So, for Q(2) (read that as "the value of the expression Q when x equals 2"), replace x everywhere with the number 2 as follows.
Q%28x%29+=+x%5E2+-3x+%2B4
Q%282%29+=+2%5E2+-3%2A2+%2B4
Q%282%29+=+4+-6+%2B4
Q%282%29+=+2+
Next you are asked to find Q(-3). (read that as "the value of the expression Q when x equals -3"). Again, replace x everywhere with the number given for x; in this case -3 as follows.
Q%28x%29+=+x%5E2+-3x+%2B4
Q%28-3%29+=+%28-3%29%5E2+-3%2A%28-3%29+%2B4
Q%28-3%29+=+9+%2B+9+%2B4
Q%28-3%29+=+22+
You do Q(0). Let me know if you still don't understand.

Answer by cooper81(1) About Me  (Show Source):
You can put this solution on YOUR website!
Q(x)=x to the 2nd power -3x + 4
Q(0)=0 to the 2nd power - 3*0 = 4
Q(0)=0-0+4
Q(0)=4