Question 142840: Dorian had some red and blue beads. he had 24 more red beads than blue beads. he gave away 2/3 of the red beads and 1/4 of the blue beads. Altogether, he gave away 104 beads. how many red beads did he have at first?
Answer by jojo14344(1513)   (Show Source):
You can put this solution on YOUR website! Okay, let's assigned "x" = # of blue beads. Likewise, knowing he had 24 more red beads than blue beads, so "x+24"= red beads, right?
Another condition, 2/3 of the red beads and 1/4 of blue beads were given away that totals to 104. To show in eqn,
2/3(red beads) + 1/4(blue beads) = 104 ---------- eqn 1
2/3(x+24) + 1/4(x) =104 got it? ------------------ eqn 1.1
continuing,
2x/3 + 48/3 +1/4(x) =104
(2/3)(x) + (1/4)(x) =104-16
(8x+3x)/12 = 88
11x = 1056
x=96, Total # of blue beads at first
Also, x+24 = 96+24 = 120, total # of red beads at first
In doubt? go back eqn 1,
2/3(120) + 1/4(96) = 104
80+24=104
104=104
Thank you,
Jojo
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