SOLUTION: Thank you in advance for your help with this problem. A piece of wire 60 inches long is cut into tow pieces and then each piece is bent into the shape of square. If the sum of th

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Thank you in advance for your help with this problem. A piece of wire 60 inches long is cut into tow pieces and then each piece is bent into the shape of square. If the sum of th      Log On


   

Question 142779This question is from textbook
: Thank you in advance for your help with this problem. A piece of wire 60 inches long is cut into tow pieces and then each piece is bent into the shape of square. If the sum of the areas of the two squares is 117 square inches find the length of each piece of wire. This question is from textbook

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
X^2+Y^2=117
4X+4Y=60
4X=60-4Y
X=60/4-4Y/4
X=15-Y
(15-Y)^2+Y^2=117
225-30Y+Y^2+Y^2=117
2Y62-30Y+225-117=0
2Y^2-30Y+108=0
2(Y^2-15Y+54)=0
2(Y-9)(Y-6)=0
Y-9=0
Y=9 ANSWER.
Y-6=0
Y=6 ANSWER.
PROOFS:
4*9+4*6=60
36=24=60
60=60
9^2+6^2=117
81+36=117
117=117