SOLUTION: Find two positive real numbers that differ by 2 and have a product of 10.

Algebra ->  Equations -> SOLUTION: Find two positive real numbers that differ by 2 and have a product of 10.       Log On


   

Question 142735: Find two positive real numbers that differ by 2 and have a product of 10.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
X(X+2)=10
X^2+2X-10=0
USING THE QUADRATIC EQUATIONx+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ WE GET:
X=(-2+-SQRT[262-4*1*-10])/2*1
X=(-2+-SQRT[4+40])/2
X=9-2+-SQRT44)/2
X=(-2+-6.63325)/2
X=(-2+6.63325)/2
X=4.63325/2
X=2.3166 ANSWER.
2.3166+2=4.3166 ANSWER.
PROOF:
2.3166*4.3166=10
10~10