SOLUTION: Mike invested $6000 for one year. He invested part of it at 9% and the rest at 11%. At the end of the year he earned $624 in interest. How much did he invest at each rate?
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-> SOLUTION: Mike invested $6000 for one year. He invested part of it at 9% and the rest at 11%. At the end of the year he earned $624 in interest. How much did he invest at each rate?
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Question 142584: Mike invested $6000 for one year. He invested part of it at 9% and the rest at 11%. At the end of the year he earned $624 in interest. How much did he invest at each rate? Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website! Total invested = 6000.
Total earned = 624.
Let x be the part invested at 0.09
Let y be the part invested at 0.11