SOLUTION: I am having trouble with this problem: I have to graph f(x)=a^3/x^2+a^2 if a=4 It would be so cool if someone could help me out on this one. Thanks!

Algebra ->  Rational-functions -> SOLUTION: I am having trouble with this problem: I have to graph f(x)=a^3/x^2+a^2 if a=4 It would be so cool if someone could help me out on this one. Thanks!      Log On


   

Question 142514: I am having trouble with this problem:
I have to graph f(x)=a^3/x^2+a^2 if a=4
It would be so cool if someone could help me out on this one. Thanks!
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=a%5E3%2F%28x%5E2%2Ba%5E2%29+
If a=4, f%28x%29+=+64%2F%28x%5E2%2B16%29+ There are NO ASYMPTOTES and NO ZEROS!!

Plot a few points:
If x=0, then f(x)=4
If x= 1, then f(x) =64/5=12.8
If x=-1, then f(x) = 64/5=12.8
If x=2, then f(x) = 64/8=8
If x=-2, then f(x) = 64/8=8
If x=4, then f(x) = 64/32=2
If x=-4, then f(x) = 64/32=2

graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C64%2F%28x%5E2%2B16%29+%29+
R^2