SOLUTION: using logarithms, solve the equation 2^3x = 7

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: using logarithms, solve the equation 2^3x = 7      Log On


   

Question 14246: using logarithms, solve the equation 2^3x = 7
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
2%5E%283x%29+=+7

3xlog(2) = log(7)
3x = log(7)/log(2)
3x = 2.80735
x = 0.93578 to 5dp.

jon.