SOLUTION: What is the vertex of the graph y = x^2 + 4x - 12 ? I've completely spaced out how to set this problem up! I'm so confused, please help! I've been racking m

Algebra ->  Linear-equations -> SOLUTION: What is the vertex of the graph y = x^2 + 4x - 12 ? I've completely spaced out how to set this problem up! I'm so confused, please help! I've been racking m      Log On


   

Question 142237: What is the vertex of the graph
y = x^2 + 4x - 12 ?


I've completely spaced out how to set this problem up!
I'm so confused, please help!
I've been racking my brain for the last 20 minutes over this problem!
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the vertex is on the axis of symmetry __ the equation is x=-b/2a

x=-4/(2*1) __ x=-2

substituting __ y=(-2)^2+4(-2)-12 __ y=-16

vertex is (-2,-16)