Question 1421: The width of a rectangle is 45% of the length. If the perimeter of the rectangle is 58cm, find its width. Found 2 solutions by usyim88hk, nofear:Answer by usyim88hk(158) (Show Source):
You can put this solution on YOUR website! let x be the length of the rectangle
45%x = width of rectangle
x+x+45%x+45%x = 58 = perimeter of the rectangle
2.9x = 58
x = 20
So the length of the rectangle is 20 cm and the width of the rectangle is 45% of 20 which is 9
You can put this solution on YOUR website! https://www.algebra.com/cgi-bin/display-illustration.mpl?tutor=nofear&illustration_name=IMG_1008.jpg&size=thumbnail