Question 141833: Find a counterexample to show that the following statement is incorrect:
"The sum of any two odd numbers is divisible by 4"
If I try 1 + 5 = 6, 6/4 = 3/2, does this disprove the above statement?
Answer by jojo14344(1513)   (Show Source):
You can put this solution on YOUR website! If you start with #1 then add the next higher odd #, the chance of being divisible by 4 is 50%. Meaning the 1st sequence of odd #'s will be, then the next won't, next will be, next won't, next will be...next won't. To show,
Starting at 1,
1+3=4, yes
1+5=6, no
1+7=8, yes
1+9=10, no
1+11=12, yes
1+13=14, no
1+15=16, yes
1+17=18, no
1+19=20, yes...
So you see the sequence, it is every other pair it is divisible by 4.
Hope this help.
Thank You,
Jojo
|
|
|
