Question 141738: Please help me with this math problem*
Find the domain of
f(x)=sqrt. sign (these numbers are inside the sqrt symbol 22/x^2-4x+4 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the domain of
f(x)=sqrt. sign (these numbers are inside the sqrt symbol 22/x^2-4x+4
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f(x) = sqrt[22/(x^2-4x+4)]
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Domain = ?
That denominator must not be zero.
It is zero when x^2-4x+4 = 0
(x-2)^2 = 0
x = 2 (so, 2 is excluded from the domain of f)
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Also, 22/x^2-4x-4 must not be negative.
It is negative when x^2-4x-2 is negative
(x-2)^2 < 0
Since (x-2) is squared, it is never negative.
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Conclusion:
Domain is all Real Numbers except x=2
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Cheers,
Stan H.
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