| 
 
 
 
Question 141735This question is from textbook Introductory Algebra  
:  The product of the smaller two of three consecutive integers is equal to 23 plus the largest.  Find the integers. 
This question is from textbook Introductory Algebra  
 Answer by ankor@dixie-net.com(22740)      (Show Source): 
You can  put this solution on YOUR website! The product of the smaller two of three consecutive integers is equal to 23 plus the largest. Find the integers. 
: 
3 consecutive integers: x, (x+1), (x+2) 
: 
Write an equation for what it says: 
x*(x+1) = 23 + (x+2) 
: 
x^2 + x = x + 25 
: 
x^2 + x - x - 25 = 0; arrange as a quadratic equation 
: 
x^2 - 25 = 0; recognize this as the "difference of square" 
Factors to: 
(x-5)(x+5) = 0 
Two solutions: 
x = +5,  (5, 6, 7 are the integers) 
and 
x = -5, (-5, -4 ,-3 can also be the integers. 
: 
Check both solutions in the original equation 
 
  | 
 
  
 
 |   
 
 |   
 |  |