Question 141734: Could you simplify these two problems?
7 over x+1 plus 3 over x-4
8 over x+4 plus 3 over 4+x
Thanks,
Carlos Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! simplify these two problems?
7 over x+1 plus 3 over x-4
(7/(x+1)) + (3/(x-4))
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least common denominator: (x+1)(x-4)
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Rewrite the fractions:
[7(x-4) + 3(x+1)]/ lcm
[10x-35]/[(x+1)(x-40]
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8 over x+4 plus 3 over 4+x
8/(x+4) + 3/(x+4)
= (8+3)/(x+4)
= 11/(x+4)
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Cheers,
Stan H.
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