SOLUTION: the original problem was 4x-1=3x+15, I was told that my answer was algebraically correct but not graphically correct(The answer I got was x=16). I should look at it like y=4x-1 and

Algebra ->  College  -> Linear Algebra -> SOLUTION: the original problem was 4x-1=3x+15, I was told that my answer was algebraically correct but not graphically correct(The answer I got was x=16). I should look at it like y=4x-1 and      Log On


   

Question 141323: the original problem was 4x-1=3x+15, I was told that my answer was algebraically correct but not graphically correct(The answer I got was x=16). I should look at it like y=4x-1 and y=3x+15. I don't understand where this came from or how to do this because if the equations are equal how will the intercept will they not be parallel lines?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
the original problem was 4x-1=3x+15, I was told that my answer was algebraically correct but not graphically correct(The answer I got was x=16). I should look at it like y=4x-1 and y=3x+15. I don't understand where this came from or how to do this because if the equations are equal how will the intercept will they not be parallel lines?
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No, not parallel; since they do not have the same slope the lines must intersect.
graph%28400%2C300%2C-10%2C20%2C-10%2C90%2C4x-1%2C3x%2B15%29
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Cheers,
Stan H.