SOLUTION: Can you solve this system of equations by using multiplication with the addition method? x/2+y/5=13/10 2x-3y=-10

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Question 140984This question is from textbook Prentice Hall Algebra 1
: Can you solve this system of equations by using multiplication with the addition method?
x/2+y/5=13/10
2x-3y=-10 This question is from textbook Prentice Hall Algebra 1

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
x/2+y/5=13/10
2x-3y=-10
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Multiply thru the 1st equation by 10.
5x+2y = 13
2x-3y =-10
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Multiply thru the 1st equation by 3 and the 2nd equation by 2 to get:
15x + 6y = 39
4x - 6y = -20
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Add to get:
19x = 19
x = 1
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Substitute into 2x-3y = -10 to solve for "y":
2*1 - 3y = -10
-3y = -12
y = 4
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Solution: x=1; y = 4
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Cheers,
Stan H.