SOLUTION: A model rocket launched straight upward with an initial velocity of 200 m/s. The height of the rocket h, in meters, can be modelled by h = -5t^2 = 200t, where t is the elapsed time

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A model rocket launched straight upward with an initial velocity of 200 m/s. The height of the rocket h, in meters, can be modelled by h = -5t^2 = 200t, where t is the elapsed time      Log On


   

Question 140949This question is from textbook Nelson Mathematics 10
: A model rocket launched straight upward with an initial velocity of 200 m/s. The height of the rocket h, in meters, can be modelled by h = -5t^2 = 200t, where t is the elapsed time in seconds. What is the maximum height the rocket reaches? This question is from textbook Nelson Mathematics 10

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the maximum of the graph lies on the axis of symmetry (at the vertex of the parabola)

the general equation for the axis of symmetry is x=-b/(2a)

in this case, t=-200/(2(-5)) __ t=-200/-10 __ t=20

substituting __ h=-5(20^2)+200(20) __ h=-2000+4000 __ h=2000