SOLUTION: A sum of money was divided between man A, B and C in the ratio 1:2:3. Sadly, Man C died, and his money was divided between man A and B in the ratio 1:3. When this happened, man B h
Algebra ->
Percentage-and-ratio-word-problems
-> SOLUTION: A sum of money was divided between man A, B and C in the ratio 1:2:3. Sadly, Man C died, and his money was divided between man A and B in the ratio 1:3. When this happened, man B h
Log On
Question 140906: A sum of money was divided between man A, B and C in the ratio 1:2:3. Sadly, Man C died, and his money was divided between man A and B in the ratio 1:3. When this happened, man B had $2000 more than man A. What is their total sum?
(Answer = 4800 but i need to know how to do it) Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! Let amount A had be x, B had be 2x and C had be 3x.
Let s be the sum.
x+2x+3x=s
since we must divide C's money in fourths, lets multiply the equation by 4.
4x+8x+12x=4s
7x+17x=4s A gets 3x and B gets 9x of C's 12x
7x/4 + 17x/4 = s Divide each side by 4
17x/4 - 7x/4 = 2000
10x/4=2000
10x=8000
x=800
x+2x+3x=s
800+1600+2400=$4800.
.
Ed
